Question

I am trying to read a Fortran double-precision number like 1.2345D+02 into python, but I got the following error:

>>> float('1.2345D+02')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for float(): 1.2345D+02

By following the advice on Python scientific notation using D instead of E, I tried numpy but I also get the same error:

import numpy
>>> numpy.float("1.2345D+02")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for float(): 1.2345D+02

Is there a solution in Python to read those double precision numbers without just changing the ‘D’ to ‘E’?

EDIT: I replaced a bad syntax on the strings. But still I get errors.

Answer 1

What’s wrong with float(str.replace("D", "E"))?

Please note, numpy DOES support fortran notation: numpy.float("1.2345D+02").

You seem to have some deeper purpose, perhaps shedding light on it would help.