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Home/ Questions/Q 6051077
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:45:42+00:00 2026-05-23T07:45:42+00:00

I am trying to read a zipped file in python. I want to read

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I am trying to read a zipped file in python. I want to read only files with “debug” in their names and only print lines which have BROKER_LOGON in them. It somehow does not read line by line, but prints the entire file which has BROKER_LOGON in it. Please tell me if there is a way to read line by line from a zipped file.

import os

import zipfile

import re

def main():
try:
    root = zipfile.ZipFile("C:/Documents and Settings/Desktop/20110526-1708-server.zip", "r")
except:
    root = "."  
for name in root.namelist():
    i = name.find("debug")
    if i>0:
        line = root.read(name).find("BROKER_LOGON")
        if line >0:
            print line


if __name__== "__main__":
    main()
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T07:45:42+00:00Added an answer on May 23, 2026 at 7:45 am
    for name in root.namelist():
        if name.find("debug") >= 0:
            for line in root.read(name).split("\n"):
                if line.find("BROKER_LOGON") >= 0:
                    print line
    

    This code reads the raw file contents with root.read(name), splits them to lines and then scans the lines.

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