I am trying to reference a variable stored in a SESSION() from a SESSION() controller and I’m having a bit of trouble with the code. What I have are two tables, one for articles and one for authors. The author id of the current user logged in is stored in my $id variable via a SQL query in access.inc.php in function databaseContainsAuthor($email, $password, &$id), then referenced in function userIsLoggedIn() and stored in $_SESSION['id']
includes>access.inc.php
<?php
function userIsLoggedIn()
{
if (isset($_POST['action']) and $_POST['action'] == 'login')
{
if (!isset($_POST['email']) or $_POST['email'] == '' or
!isset($_POST['password']) or $_POST['password'] == '')
{
$GLOBALS['loginError'] = 'Please fill in both fields';
return FALSE;
}
$password = md5($_POST['password'] . 'chainfire db');
if (databaseContainsAuthor($_POST['email'], $password, $id))
{
include 'db.inc.php';
session_start();
$_SESSION['loggedIn'] = TRUE;
$_SESSION['email'] = $_POST['email'];
$_SESSION['password'] = $password;
$_SESSION['id'] = $id;
return TRUE;
}
else
{
session_start();
unset($_SESSION['loggedIn']);
unset($_SESSION['email']);
unset($_SESSION['password']);
unset($_SESSION['id']);
$GLOBALS['loginError'] = 'The specified email address or password was incorrect.';
return FALSE;
}
}
if (isset($_POST['action']) and $_POST['action'] == 'logout')
{
session_start();
unset($_SESSION['loggedIn']);
unset($_SESSION['email']);
unset($_SESSION['password']);
unset($_SESSION['id']);
header('Location: ' . $_POST['goto']);
exit();
}
session_start();
if (isset($_SESSION['loggedIn']))
{
return databaseContainsAuthor($_SESSION['email'], $_SESSION['password'], $_SESSION['id']);
}
}
function databaseContainsAuthor($email, $password, &$id)
{
include 'db.inc.php';
$email = mysqli_real_escape_string($link, $email);
$password = mysqli_real_escape_string($link, $password);
$sql = "SELECT COUNT(*) FROM author
WHERE email='$email' AND password='$password'";
$result = mysqli_query($link, $sql);
if (!$result)
{
$error = 'Error searching for author.';
include 'error.html.php';
exit();
}
$row = mysqli_fetch_array($result);
$sql = "SELECT id FROM author
WHERE email='$email'";
$id = mysqli_query($link, $sql);
if (!$id)
{
$error = 'Error searching for id.';
include 'error.html.php';
exit();
}
if ($row[0] > 0)
{
return TRUE;
}
else
{
return FALSE;
}
}
Now that I have the variable $id, which contains the current user’s id, stored in $_SESSION['id'], I would like to use the SESSION() in a SQL query in my index.php to insert the author’s id along with their articles in my article table so the author and the article the author submits are linked. I’m just having a bit of trouble implementing the correct code to reference $_SESSION['id'] in my SQL query for index.php
articles>index.php
<?php
include_once $_SERVER['DOCUMENT_ROOT'] .
'/includes/magicquotes.inc.php';
include $_SERVER['DOCUMENT_ROOT'] .
'/includes/access.inc.php';
if (isset($_GET['add']))
if (!userIsLoggedIn())
{
include $_SERVER['DOCUMENT_ROOT'] . '/includes/login.inc.html.php';
exit();
}
else
{
$pagetitle = 'New Article';
$action = 'addform';
$text = '';
$authorid = '';
$id = '';
$button = 'Add article';
include 'form.html.php';
exit();
}
if (isset($_GET['addform']))
{
include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';
$text = mysqli_real_escape_string($link, $_POST['text']);
$id = $_SESSION['id'];
$sql = "INSERT INTO article SET
articletext='$text',
articledate=CURDATE(),
authorid= '$id'";
if (!mysqli_query($link, $sql))
{
$error = 'Error adding submitted article: ' . mysqli_error($link);
include 'error.html.php';
exit();
}
header('Location: .');
exit();
}
include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php';
$result = mysqli_query($link, 'SELECT id, articletext FROM article');
if (!$result)
{
$error = 'Error fetching articles: ' . mysqli_error($link);
include 'error.html.php';
exit();
}
while ($row = mysqli_fetch_array($result))
{
$articles[] = array('id' => $row['id'], 'text' => $row['articletext']);
}
include 'articles.html.php';
?>
The SESSION() I’m trying to reference is under if (isset($_GET['addform'])), but I;m unsure if this is the rite syntax to use to do so. Any help would be greatly appreciated!
The code seems fine.Check if $id has the value you expect it to be just before the query because if it is returning zero every time your authorid must have some default value which always show up,zero in this case.