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Home/ Questions/Q 7565249
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T14:06:22+00:00 2026-05-30T14:06:22+00:00

I am trying to replace the words in a sentence using preg_replace_callback . %1%

  • 0

I am trying to replace the words in a sentence using preg_replace_callback.

"%1% and %2% went up the %3%"

should become

"Jack and Jill went up the hill"

I have given my code below.

<?php
  $values = array("Jack", "Jill", "hill");
  $line = "%1% and %2% went up the %3%";
  $line = preg_replace_callback(
    '/%(.*?)%/',
    create_function(
        // single quotes are essential here,
        // or alternative escape all $ as \$
        '$matches',
        'return $values[$matches[1]-1];'
    ),
    $line
  );
  echo $line;
?>

What I am getting is

" and went up the "

If I give return $matches[1]-1; , I am getting

"0 and 1 went up the 2"

Is it a scope issue ? How to make this working ?
Any help would be appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T14:06:23+00:00Added an answer on May 30, 2026 at 2:06 pm

    It is indeed a scoping issue – your anonymous function created by create_function does not have access to $values.

    This should work (>= PHP 5.3.0)

    <?php
      $values = array("Jack", "Jill", "hill");
      $line = "%1% and %2% went up the %3%";
      // Define our callback here and import $values into its scope ...
      $callback = 
        function ($matches) use ($values)
        {
          return $values[$matches[1]-1];
        };
    
      $line = preg_replace_callback(
        '/%(.*?)%/',
        $callback, // Use it here.
        $line
      );
      echo $line;
    ?>
    

    By declaring the callback function with use ($values), $values will be imported into its scope and available when it’s called. This is the concept of a ‘closure’ over $values if you’d like to Google it further :).

    Hope this helps.

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