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Home/ Questions/Q 6777731
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:10:57+00:00 2026-05-26T16:10:57+00:00

I am trying to retrieve content from xml tagnames from a url, but my

  • 0

I am trying to retrieve content from xml tagnames from a url, but my int numberOfDetails has a length of 0. What am I doing wrong?

//Edited Code

public String[] dumpTitles(String[] xmlFiles) {


        String[] elementsArray = null;
        try { 
            URL xmlContent = new URL("http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml");
            DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
            Document doc = db.parse(new InputSource(xmlContent.openStream()));


            Toast.makeText(this, "xml file: " + xmlContent, 1000).show();

            NodeList detailsNodeList = doc.getElementsByTagName("Details");
            int numberOfDetails = detailsNodeList.getLength();
            String str = String.format("There are %d Details elements", numberOfDetails);
            Log.println(Log.DEBUG, TAG, str);
            Toast.makeText(this, "number of details: " + str, 1000).show();
            elementsArray = getElementByTagName("ProductName", numberOfDetails, detailsNodeList);
        }
        catch (Exception ex) {
            Log.println(Log.DEBUG, TAG, "XML Parsing failed: " + ex.getMessage());
        }

        return elementsArray;  

    }

  public String[] getElementByTagName(String detailTagName, int numberOfDetails, NodeList detailsNodeList) throws Exception {
      String[] elementsArray = null;
      ArrayList<String> elementsArrayList = new ArrayList<String>();
      Toast.makeText(this, "TEST2", 1000).show();
        for (int k = 0; k < numberOfDetails; k++) {
            Toast.makeText(this, "TEST3", 1000).show();
            Element nDetails = (Element)detailsNodeList.item(k);
            NodeList elementNodeList = ((Document) nDetails).getElementsByTagName(detailTagName);
            Node nodeName = elementNodeList.item(k);
            String nodeString = String.format("%s", nodeName);
            elementsArrayList.add(nodeString);
            elementsArray = elementsArrayList.toArray(elementsArray);
            Log.println(Log.DEBUG, TAG, nodeString);
            Toast.makeText(this, "TEST4", 1000).show();
            Toast.makeText(this, "ELEMENT" + elementsArray[0], 1000).show();

        }

        return elementsArray;
}

// Original Code
String xmlContent = “http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml&#8221;;
Log.println(Log.DEBUG, TAG, “FILE NAME: ” + xmlContent);
String[] elementsArray = null;
try {
DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Toast.makeText(this, “xml file: ” + xmlContent, 1000).show();
Document doc = db.parse(new InputSource(new StringReader(xmlContent)));
NodeList detailsNodeList = doc.getElementsByTagName(“Details”);
int numberOfDetails = detailsNodeList.getLength();

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:10:58+00:00Added an answer on May 26, 2026 at 4:10 pm

    You shouldn’t use StringReader to read from url. StringReader reads string you passed in constructor, it doesn’t download file from the web. You can use URL class instead:

    URL xmlContent = new URL("http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml");
    DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
    Document doc = db.parse(new InputSource(xmlContent.openStream()));
    

    Another way:

    You can use constructor of InputSource which takes String:

    String pathToDocument = "http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml";
    Document doc = db.parse(new InputSource(pathToDocument));
    
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