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Home/ Questions/Q 7729589
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:00:17+00:00 2026-06-01T06:00:17+00:00

I am trying to retrieve RSS feed from Yahoo SQL API and storing it

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I am trying to retrieve RSS feed from Yahoo SQL API and storing it in a file through PHP. Here is the code:

if( filemtime($cache) < (time() - 10800) ) {

   if ( !file_exists(dirname(__FILE__) . '/cache') ) {
      mkdir(dirname(__FILE__) . '/cache', 0777);
   }

   $path = "http://query.yahooapis.com/v1/public/yql?q=";
   $path .= urlencode("SELECT * FROM feed WHERE url='http://url'");
   $path .= "&format=json";

   $feed = file_get_contents($path, true);

   if ( is_object($feed) && $feed->query->count ) {
      $cachefile = fopen($cache, 'wb');
      fwrite($cachefile, $feed);
      fclose($cachefile);
   }
}
else {
   $feed = file_get_contents($cache);
}

The problem is. Now I want to store the results in the database. but since, I am storing it in the file and updating it within 3 hours, I am certain that I will run in to duplicate RSS entries. And I don’t want to store those duplicates in the DB.

Is there some efficient approach to getting this done?

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:00:18+00:00Added an answer on June 1, 2026 at 6:00 am

    Or you add a unique index on url, that way an insert will not be added if the url already exists.

    You can ingore the error mysql gives you by using INSERT INGORE INTO …

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