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Home/ Questions/Q 1003151
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:56:09+00:00 2026-05-16T07:56:09+00:00

I am trying to return a variable from onreadystatechange and seem to be having

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I am trying to return a variable from onreadystatechange and seem to be having trouble with scope. Even if I set a global variable, when trying to retrieve my variable after the fact, its undefined. Not quite sure what I am doing wrong. I haven’t done too much work with Javascript in the past 3 years.

var lat;
var lon;

 window.onload = function dosomething(){

  var myRequst = new XMLHttpRequest();

  var url = "http://www.instamapper.com/api?action=getPositions&key=584014439054448247";

  myRequst.open('get', url);

  myRequst.onreadystatechange = function(){

  if ((myRequst.readyState == 4) && (myRequst.status == 200)){

  //alert(myRequst.responseText);

   var data = myRequst.responseText;
   collected=data.split(",");   //parses the data delimited by comma and put data into array

lat = collected[4];
lon = collected[5];

document.write("latitude "+lat+"<BR>\n");
document.write("latitude "+lon+"<BR>\n");

  }

  }

  myRequst.send(null);


 }

document.write(lat);

Any help or suggestions would be much appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:56:10+00:00Added an answer on May 16, 2026 at 7:56 am

    You have to use a callback function which will handle the data. Remember AJAX stands for Asynchronous(JAX). So if after your onreadystatechange handling the value is not yet available is because the request did not complete at that moment.

    myRequest.onreadystatechange = function() {
      if(myRequest.readyState == 4 && myRequest.status == 200) {
        (function(data) {
          // do something with the response in the variable data
        })(myRequest.responseText);
      }
    }
    

    Edit: also you can follow the request in the net/console tab of firebug to see exactly if an error has occured

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