I am trying to return a variable with values of an array of users. There are a few conditions that must be met. The user must have public_find set to true, it must not be the current_user (session variable of the user currently logged in), and it must not already be part of a friendship. The first and second conditions work perfectly. However, I am having an issue with the third part where the current_users.friendships needs to be an array of the ID values of the users where the association already exists. Any thoughts?
@users = User.find(:all, :conditions => ['
public_find=true AND
id <> ? AND
id NOT IN (?)',
current_user.id, current_user.friendships])
Edit:
I’ve figured out that I was missing pluck from the list. This works good now. However, if someone does not yet have a friend then current_user.friendships.pluck(:friend_id) will return NULL. I know that it is bad practice and unexpected results returned when using NOT IN and NULL. However, how do you create a condition where you can set the value to something realistic like [0] or [1] if the array returned is empty?
@users = User.find(:all, :conditions => ['
public_find=true AND
id <> ? AND
id NOT IN (?)',
current_user.id, current_user.friendships.pluck(:friend_id) || [0]])
EDIT AGAIN:
I got it working. However, now I want to know if this is best practice to have a statement like this. It basically is doing a check to see if the current_user.friendships.pluck(:friend_id) is empty or not. If it is then return [0]. Otherwise return an array of the user ids (foreign keyed as friend_id).
@users = User.find(:all, :conditions => ['
public_find=true AND
id <> ? AND
id NOT IN (?)',
current_user.id,
(current_user.friendships.pluck(:friend_id).empty? ? [0] : current_user.friendships.pluck(:friend_id))])
You can write this a little nicer ..
Show all users where public_find is true and also exclude the currently logged in user or any of their friends