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Home/ Questions/Q 8524987
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T07:50:41+00:00 2026-06-11T07:50:41+00:00

I am trying to run a desktop application which is developed in java rmi.

  • 0

I am trying to run a desktop application which is developed in java rmi. While I am trying to execute this application in eclipse, I am getting following error. Please any one help me thanks in advance.

Exception in thread "main" java.security.AccessControlException: access denied (java.util.PropertyPermission * read,write)
    at java.security.AccessControlContext.checkPermission(Unknown Source)
    at java.security.AccessController.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkPropertiesAccess(Unknown Source)
    at java.lang.System.getProperties(Unknown Source)
    at .HeadOfficeManager.Manager.main(Manager.java:103)

Here is the code.

public static void main(String args[])
{
    Manager frame = new Manager();
    frame.setVisible(true);
    // frame.show(); old 1.4

    // Create and install a security manager
    if (System.getSecurityManager()== null)
    {
        System.setSecurityManager(new RMISecurityManager());
    }
    try
    {
        Properties prop = System.getProperties();
        String httpPath = prop.getProperty("HTTPPath");
        new ClassFileServer(80, httpPath);
    }
    catch (IOException e)
    {}

    try
    {
        java.rmi.registry.LocateRegistry.createRegistry(1099);
        System.out.println("RMI registry ready.");
    }
    catch (Exception e)
    {
        System.out.println("Exception starting RMI registry:");
        e.printStackTrace();
    }
    try
    {
        RMIHandler = new ManagerRMIHandler();

        // Bind the remote object's stub in the registry
        Registry registry = LocateRegistry.getRegistry();
        registry.rebind("HeadOfficeManager", RMIHandler);

        System.err.println("Server ready");
    }
    catch (Exception e)
    {
        System.err.println("Server exception: " + e.toString());
        e.printStackTrace();
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T07:50:43+00:00Added an answer on June 11, 2026 at 7:50 am
    1. Right click on application in eclipse and click on run configurations.
    2. Add virtual machine arguments as -Djava.security.policy =java.policy.applet.
    3. Create a file, name it as java.policy.applet.
    4. Add below lines in that file.

      grant  
      {  
          permission java.security.AllPermission;  
      };
      
    5. Save it and run the application.

    This will give all security permissions to your Java application.

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