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Home/ Questions/Q 6563989
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:54:42+00:00 2026-05-25T13:54:42+00:00

I am trying to run a program like this: $CMD $ARGS where $ARGS is

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I am trying to run a program like this:

$CMD $ARGS

where $ARGS is a set of arguments with spaces. However, zsh appears to be handing off the contents of $ARGS as a single argument to the executable. Here is a specific example:

$export ARGS="localhost -p22"
$ssh $ARGS
ssh: Could not resolve hostname localhost -p22: Name or service not known

Is there a bash or zsh flag that controls this behavior?

Note that when I put this type of command in a $!/bin/sh script, it performs as expected.

Thanks,

SetJmp

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:54:42+00:00Added an answer on May 25, 2026 at 1:54 pm

    It will work if you use eval $CMD $ARGS.

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