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Home/ Questions/Q 6654101
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:20:59+00:00 2026-05-26T01:20:59+00:00

I am trying to see how getopts work. I wrote the code below but

  • 0

I am trying to see how getopts work. I wrote the code below but not sure what I am doing wrong. Please point me :

#include<unistd.h>
.. 
..
int main( int argc, char *argv[])
{
  int ch=0;
   while((ch=getopt(argc, argv, "ltR:")!=-1) // 0 here was by mistake. Changed to -1
    {  
      printf("%d",ch); //This prints -1 
       switch(ch)
               {
                 case 'l':
                 printf("l");
                 break;
                 case 't':
                 printf("t");
                 break;
                 case 'R':
                 printf("R");
                 break;
                }
    }
   return 0;
 }

 $ ./a.out -ltR 
 $ -1
 $ ./a.out -l 
 $ -1

May be I am doing a really mistake or missing out on some aspect of my understanding of getopt.

Made changes but still gives the same result:(

Thanks,
Faizan

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:21:00+00:00Added an answer on May 26, 2026 at 1:21 am

    I think your while expression should be

    while((ch=getopt(argc, argv, "ltR")!=-1)
    {..}
    

    and the option should end with ‘:’

    while((ch=getopt(argc, argv, "ltR:")!=-1)
    {..}
    

    or two ‘:’ if switch is optional.

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