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Editorial Team
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Asked: 2026-05-14T06:50:09+00:00

I am trying to send raw xml to a service in Python. I have

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I am trying to send raw xml to a service in Python. I have a the address of the service and my question is how would I wrap XML in python and send it to the service. The address is in the format below.

192.1100.2.2:54239

And say the XML is:

<xml version="1.0" encoding="UTF-8"><header/><body><code><body/>

Anyone know what to do?

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1 Answer

  1. Editorial Team

    This should do the trick.

    import socket
import time

command = '<xml version="1.0" encoding="UTF-8"><header/><body><code><body/>'

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(("192.1100.2.2", 54239))

s.send(command)

time.sleep(2)
resp = s.recv(3000)

print resp
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