Question

I am trying to set a switch based on a comparison of the result from mySQL table query. The query works if I am using a print or echo, but throws a syntax error when trying to use the exact same loop for a comparison. Code for comparison that throws the error is below.

//Define query for database entry lookup
$sql = "SELECT * FROM email_auth WHERE useremail='$user_email_address'";

//Define result for database entry lookup
$result = mysql_query($sql) or die(mysql_error());

//Find match for email authentication
$email_count = 0;
while($row = mysql_fetch_assoc($result)){
  if ( $row['authID'] == $user_email_auth ) { $validemailrequest = "true" }  //Line 60
  $email_count++;
}

And the error I am getting…

<b>Parse error</b>:  syntax error, unexpected '}' in
<b>/home/user/public_html/send_email.php</b> on line <b>60</b>

Yet works when using same for print…

//Define query for database entry lookup
$sql = "SELECT * FROM email_auth WHERE useremail='$user_email_address'";

//Define result for database entry lookup
$result = mysql_query($sql) or die(mysql_error());

//Find match for email authentication
$email_count = 0;
while($row = mysql_fetch_assoc($result)){
  print $row['authID'];
  $email_count++;
}

Answer 1

There seems to be a semi-colon missing after the conditional code.

while($row = mysql_fetch_assoc($result)){
    if ( $row['authID'] == $user_email_auth ) { $validemailrequest = "true"; }  //Line 60
    $email_count++;
}