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Home/ Questions/Q 6574751
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T15:18:01+00:00 2026-05-25T15:18:01+00:00

I am trying to set the success_url on a django class based UpdateView but

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I am trying to set the success_url on a django class based UpdateView but cannot get it to work. I have tried the syntax suggested in the docs

success_url="/polls/%(slug)s/"

But it is not working. How can I access the model fields in the success_url?

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  1. Editorial Team
    Editorial Team
    2026-05-25T15:18:02+00:00Added an answer on May 25, 2026 at 3:18 pm

    This relies on object field attributes. In the example you’ve posted, the model should have a slug field.

    For related fields:

    You can try using django’s __ notation for related objects (e.g: user__username) in success_url, not sure if it’ll work.

    IMO in such cases a better practice is overriding get_success_url(), and returning the url taking into account self.object.

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