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Home/ Questions/Q 7767891
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:47:08+00:00 2026-06-01T15:47:08+00:00

I am trying to show a Dialog box on onPostExecute method of an AsyncTask

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I am trying to show a Dialog box on onPostExecute method of an AsyncTask

@Override
protected void onPostExecute(HttpResponse response) {
if (response == null) {
            Log.d(TAG, "onPostExecute, response == null");
            AlertDialog.Builder builder = new AlertDialog.Builder(ConfirmPhoneNoCode.this);
            builder.setMessage("Are you sure you want to exit?").setCancelable(false)
                    .setPositiveButton("Yes", new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int id) {
                            ConfirmPhoneNoCode.this.finish();
                        }
                    }).setNegativeButton("No", new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int id) {
                            dialog.cancel();
                        }
                    });
            AlertDialog alert = builder.create();
        } else {
            int responseCode = response.getStatusLine().getStatusCode();
            String message = response.getStatusLine().getReasonPhrase();
            Log.d(TAG, "Response Code: " + String.valueOf(responseCode));
            Log.d(TAG, "Message: " + message);
        }
    }

I am getting the log message

03-31 23:02:42.912: D/ConfirmPhoneCode(21966): onPostExecute, response == null

that means

if(response == null) is executed but AlertDialog box don't show-up.

I will appreciate if someone could help me with this.

Thanks in Advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T15:47:09+00:00Added an answer on June 1, 2026 at 3:47 pm

    alert.show(); I think you have to add it…

    AlertDialog alert = builder.create();
    alert.show();
    
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