Question

I am trying to sort a list of tuples based on another list of tuples by a key in that list.

Say I have the following:

list1 = [(5, 'something'),(2,'bobby'),(9,'suzy'),(6,'crab')]
list2 = [('something','othervalues'),('suzy','stuff'),('bobby','otherthings')]

And from this I would receive the output soring on the first element of each tuple in list1.

sorted = [('suzy','stuff'),('something','othervalues'),('bobby','otherthings') ]

So essentially it performs an intersection and then sorts on the remaining values by the first element in the tuple of list1.

I am not sure how to go about this, so any help would be great.

Answer 1

Just do what the description says, sort a list of tuples based on another list of tuples by a key in that list:

rank = {key:rank for rank, key in list1}
print(sorted(list2, key=lambda t: rank.get(t[0]), reverse=True))