Home/ Questions/Q 748039
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-14T14:16:27+00:00

I am trying to sort by date and get an error message about the

  • 0

I am trying to sort by date and get an error message about the stylesheet can’t be loaded

I found an answer on how others have suggested but it doesn’t work for me

Here is where it is supposed to sort. The commented out line is where the sort should occur

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

 <xsl:template name="hoo" match="/">
  <html>
   <head>
    <title>Registered Festival Organisers and Festivals</title>
    <link rel="stylesheet" type="text/css" href="userfestival.css" />
   </head>
   <body>
    <h1>Registered Festival Organisers and Festivals</h1>

    <xsl:for-each select="folktask/member">

     <xsl:if test="user/account/userlevel='3'">
      <!--<xsl:sort select="concat(substring(festival/event/datefrom,1,4),substring(festival/event/datefrom, 6,2),substring(festival/event/datefrom, 9,2))" data-type="number" order="ascending"/>-->

Sample node from XML

    <festival id="1">
     <event>
      <eventname>Oxford Folk Festival</eventname>
      <url>http://www.oxfordfolkfestival.com/</url>
      <datefrom>2010-04-07</datefrom>
      <dateto>2010-04-09</dateto>
      <location>Oxford</location>
      <eventpostcode>OX1 9BE</eventpostcode>
      <coords>
       <lat>51.735640</lat>
       <lng>-1.276136</lng>
      </coords>
     </event>
    </festival>
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    There is no need to make complicated string manipulations that turn <datefrom> into a number. Dates in the yyyy-mm-dd format sort perfectly well as text.

    <xsl:for-each select="folktask/member[user/account/userlevel='3']">
  <xsl:sort select="festival/event/datefrom" />
  <!-- ... -->
</xsl:for-each>
    • 0