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Home/ Questions/Q 6923111
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:29:37+00:00 2026-05-27T10:29:37+00:00

I am trying to spawn a new process using execve() from unistd.h on Linux.

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I am trying to spawn a new process using execve() from unistd.h on Linux. I have tried passing it the following parameters execve("/bin/ls", "/bin/ls", NULL); but get no result. I do not get an error either, the program just exits. Is there a reason why this is happening? I have tried launching it as root and regular user. The reason I need to use execve() is because I am trying to get it to work in an assembly call like so

program: db "/bin/ls",0

mov eax, 0xb
mov ebx, program
mov ecx, program
mov edx, 0
int 0x80

Thank you!

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:29:37+00:00Added an answer on May 27, 2026 at 10:29 am

    The arguments that you’re passing to execve are wrong. Both the second and third must be an array of char pointers with a NULL sentinel value, not a single pointer.

    In other words, something like:

    #include <unistd.h>
    int main (void) {
        char * const argv[] = {"/bin/ls", NULL};
        char * const envp[] = {NULL};
        int rc = execve ("/bin/ls", argv, envp);
        return rc;
    }
    

    When I run that, I do indeed get a list of the files in the current directory.

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