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Home/ Questions/Q 8528989
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T08:55:36+00:00 2026-06-11T08:55:36+00:00

I am trying to store an SSE type in an stl container. I’ve tried

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I am trying to store an SSE type in an stl container. I’ve tried this:

#include <iostream>
#include <vector>

int main()
{
  typedef int v4sf __attribute__ (( vector_size(4*sizeof(float)) ));

  v4sf a; // compiles

  std::vector<v4sf> v1; // compiles, but nothing is actually allocated

//  std::vector<v4sf> v2(10); // compiler error: can’t convert between vector values of different size

  std::vector<v4sf> v(10, a); // Compiles, but segfaults

  return 0;
}

but as noted, allocating without providing an object to copy produces a compiler error, while allocating with providing an object compiles but segfaults. Can anyone explain why I can’t store these SSE objects in an STL container like this (or better, provide a correct way to do it)?

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  1. Editorial Team
    Editorial Team
    2026-06-11T08:55:37+00:00Added an answer on June 11, 2026 at 8:55 am

    To make it working, you have to implement a custom Allocator. To use it, it is the argument next to the type:
    std::vector< SSEType, CustomAlloc> container;
    Where CustomAlloc is the Allocator.
    You have to use an alligned_malloc or memalign for getting memory inside of your Allocater, but this is the way to succeed here.

    An example of such a (not so easy implementation) can be found here:
    Implementing Allocator example

    I did already much with SSE and I observed, it is the most easy way to use an alligned malloc and use this for my calculations.

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