Question

I am trying to translate the following cshell command to bash
but I am not sure what it does and how I can translate it
to bash.

./runall |& fold -w 80 |& tee ${log_file}

Any help appreciated,

Ted

Answer 1

foo |& bar executes foo with its stdout and stderr piped to the stdin of bar.

The bash equivalent is foo 2>&1 | bar.

So for your command, it should be (untested):

./runall 2>&1 | fold -w 80 2>&1 | tee ${log_file}

(The curly braces in ${log_file} aren’t really necessary, but they’re harmless, and some consider them to be a good idea; that’s true for both csh and bash.)