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Home/ Questions/Q 7430135
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T09:05:25+00:00 2026-05-29T09:05:25+00:00

I am trying to turn this C code: if (op == ‘+’) { acc

  • 0

I am trying to turn this C code:

    if (op == '+') {
      acc += val;
    }

into MIPS, and I can’t figure out what is causing the address out of range error

#reads user input for the op
li $v0, 12      # system call number for operator
syscall         # reads the integer
sw $v0, op      # stores the user input in op


lw $t0, op      # stores op in $t0
lbu $t1, '+'        # stores '+' in $t1

# "if" statement
bne $t0, $t1, Else  # branches if op is not equal to +
lw $t2, acc     # stores acc in $t2
lw $t3, val     # stores val in $t3

add $t2, $t2, $t3   # adds $t2 and $t3 and stores the sum in $t2

Any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-29T09:05:26+00:00Added an answer on May 29, 2026 at 9:05 am
    lbu $t1, '+'
    

    ‘+’ is not a valid address. You probably meant

    li $t1, '+'
    

    Anyway remember that any decent C compiler will convert C to MIPS for you.

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