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Home/ Questions/Q 826403
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:24:35+00:00 2026-05-15T03:24:35+00:00

I am trying to understand how to assign by "reference" to a class field

  • 0

I am trying to understand how to assign by "reference" to a class field in C#.

I have the following example to consider:

 public class X
 {

     public X()
     {
         string example = "X";

         new Y(ref example);

         new Z(ref example);

         System.Diagnostics.Debug.WriteLine(example);
     }

 }

 public class Y
 {

     public Y( ref string example )
     {
         example += " (Updated By Y)";
     }

 }

 public class Z
 {
     private string _Example;

     public Z(ref string example)
     {

         this._Example = example;

         this._Example += " (Updated By Z)";
     }
 }

 var x = new X();

When running the above code the output is:

X (Updated By Y)

And not:

X (Updated By Y) (Updated By Z)

As I had hoped.

It seems that assigning a "ref parameter" to a field loses the reference.

Is there a way to keep hold of the reference when assigning to a field?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T03:24:36+00:00Added an answer on May 15, 2026 at 3:24 am

    No. ref is purely a calling convention. You can’t use it to qualify a field. In Z, _Example gets set to the value of the string reference passed in. You then assign a new string reference to it using +=. You never assign to example, so the ref has no effect.

    The only work-around for what you want is to have a shared mutable wrapper object (an array or a hypothetical StringWrapper) that contains the reference (a string here). Generally, if you need this, you can find a larger mutable object for the classes to share.

     public class StringWrapper
     {
       public string s;
       public StringWrapper(string s)
       {
         this.s = s;
       }
    
       public string ToString()
       {
         return s;
       }
     }
    
     public class X
     {
      public X()
      {
       StringWrapper example = new StringWrapper("X");
       new Z(example)
       System.Diagnostics.Debug.WriteLine( example );
      }
     }
    
     public class Z
     {
      private StringWrapper _Example;
      public Z( StringWrapper example )
      {
       this._Example = example;
       this._Example.s += " (Updated By Z)";
      }
     }
    
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