Question

I am trying to update a field’s value if a string column is between two numbers.

UPDATE SAMPLE.EXAMPLE 
SET modNum = CONCAT(modNum,"26")
WHERE modNum NOT LIKE '%26%' 
  AND (procKey BETWEEN 90000 AND 99123 OR procKey = 77444);

Unfortunately I get an error:

Error Code: 1292. Truncated incorrect DOUBLE value: ‘4123F ‘

I am surprised because when I do a select I get the expected results.

SELECT *
FROM SAMPLE.EXAMPLE 
WHERE modNum NOT LIKE '%26%' 
  AND (procKey BETWEEN 90000 AND 99123 OR procKey = 77444);

Create table statement:

'CREATE TABLE `example` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `modNum` char(4) DEFAULT NULL,
  `procKey` char(8) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=7 DEFAULT CHARSET=latin1'

Sample Data:

INSERT INTO `SAMPLE`.`EXAMPLE` (`modNum`, `procKey`) VALUES ('42', '99001');
INSERT INTO `SAMPLE`.`EXAMPLE` (`modNum`, `procKey`) VALUES ('42', '9900f');

What can I do to update the columns given my conditions?

---

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To me it looks like a bug. The best I can come up with is to check if the value of procKey is an integer by using regular expressions. I changed my UPDATE statement to be:

UPDATE SAMPLE.EXAMPLE 
SET modNum = CONCAT(modNum,"26") 
WHERE modNum NOT LIKE '%26%' 
    AND procKey REGEXP '^[0-9]+$' 
    AND (procKey BETWEEN 90000 AND 99123 
        OR procKey = 77444);

Please, let me know if there is a better way.

Answer 1

To me it looks like a bug. The best I can come up with is to check if the value of procKey is an integer by using regular expressions. I changed my UPDATE statement to be:

UPDATE SAMPLE.EXAMPLE 
SET modNum = CONCAT(modNum,"26") 
WHERE modNum NOT LIKE '%26%' 
    AND procKey REGEXP '^[0-9]+$' 
    AND (procKey BETWEEN 90000 AND 99123 
        OR procKey = 77444);

Please, let me know if there is a better way.