Question

I am trying to upload a file to django. So, I tried to use the code below to create a dynamic path for the file. But, it does not work.

I actually not sure how to use instance in model.py and how to pass path to def get_file_path.
Specifically, What I want is that pass the file path from the function in views.py.
For example, when I call something like docfile.save(filepath) , it will be saved in that filepath in django. Can you help me for this?

An example:

 docfile.save(path1)

it will be saved in /path1/file_name

Note: path1 could be anything and it is not related to any model field.

Answer 1

You could for example have an extra field (e.g. path) on the model that specifies the path which you could then access via instance.path in get_file_path. You can’t access arguments to save in this function.