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Editorial Team
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Asked: 2026-05-12T20:29:57+00:00

I am trying to upload an image to the server. I hava a form

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I am trying to upload an image to the server.

I hava a form with a couple of inputs…
INSIDE this form, I have an Iframe which contains another form for the upload, this because I dont want the original form to submit().

The original form basically:

      <form> ...... bla bla bla alot of inputs....<iframe src="pic_upload.html"></iframe></form>

Here is pic_upload.html:

      </head>
      <body><form name="pic_form" id="pic_form" action="bincgi/imageUpload.php" method="post" target="pic_target"><input name="pic_file" type="file" id="pic_file" size="35" onchange="this.form.submit();"></form><div id="pic_target" name="pic_target" style="width:80px; height:80px;"></div></body>
      </html>

Here is imageUpload.php:

      <?php
      $destination_path = getcwd().DIRECTORY_SEPARATOR;
      //echo $destination_path;
      $result = 0;
      $target_path = $destination_path . basename($_FILES['pic_file']['name']);
      if(@move_uploaded_file($_FILES['pic_file']['tmp_name'], $target_path)) {
      $result = 1;
      }
      ?>

I get this error: Undefined index: pic_file on line 5 in imageUpload.php

ALSO, if I get this to work, is there a good way to display the uploaded image inside the target of the form?

Thanks alot!
PS: I will add javascript to the tags because maybe thats what I need here!

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1 Answer

  1. Editorial Team

    Don’t forget about form attribute

    enctype="multipart/form-data"
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