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Home/ Questions/Q 8848495
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T12:26:10+00:00 2026-06-14T12:26:10+00:00

I am trying to use a javascript function defined outside of the $(document).ready(function(){}); as

  • 0

I am trying to use a javascript function defined outside of the $(document).ready(function(){}); as the callback for a $.get() request. However, firebug shows:

ReferenceError: temp is not defined
    $.get('twitter.php', function(data){temp(data)});

Here’s the relevant code:

<script src="http://code.jquery.com/jquery-1.8.2.js"></script>
<script type="txt/javascript">       
    function temp(data){
        alert(data);
    }
</script>
<script>
    $(document).ready(function() {
        $.get('twitter.php', function(data){temp(data)});
    });
</script>

twitter.php does return data.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T12:26:11+00:00Added an answer on June 14, 2026 at 12:26 pm

    You have your script type set to 'txt/javascript', if I’m not mistaen, it should be 'text/javascript', also you need a semicolon after your function.

    <script type="text/javascript">       
        function temp(data){
            alert(data);
        };
    </script>
    
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