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Home/ Questions/Q 6039325
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T06:21:06+00:00 2026-05-23T06:21:06+00:00

I am trying to use a priority Queue and was trying to get the

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I am trying to use a priority Queue and was trying to get the numbers arranged in the reverse order [descending orders].

I implemented a comparator, and used the reverse convention as compared to natural order hoping that I would get numbers in reverse order.

 public static void main(String[] args)
    { 
        PriorityQueue<Integer> Descending = new PriorityQueue<Integer>(10,stats.new    
        minComparator());

        Descending.add(5);
        Descending.add(2);
        Descending.add(7);

        while(Descending.size() > 0)
        {
               System.out.print(Descending.remove());

        }    

    }

class minComparator implements Comparator<Integer>
{

    @Override
    public int compare(Integer int1, Integer int2)
    {
        if(int1.intValue() < int1.intValue())
            return 1;
        else if(int1.intValue() > int1.intValue())
            return -1;
        else
            return 0;
    }

}

Here is the output:

5 7 2

This is neither ascending nor descending !. Can someone please help me out.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-23T06:21:07+00:00Added an answer on May 23, 2026 at 6:21 am

    You compare the same number int1 to itself instead of int1 and int2

    int1.intValue() < int1.intValue()
    
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