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Home/ Questions/Q 8336885
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T04:07:42+00:00 2026-06-09T04:07:42+00:00

I am trying to use curl with google calculator to get currency conversions from

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I am trying to use curl with google calculator to get currency conversions from this url: http://www.google.com/ig/calculator?hl=en&q=100RUB=?EUR. But the following code always returns 0:

<?php

function currency($from_Currency, $to_Currency, $amount) {
    $amount = urlencode($amount);
    $from_Currency = urlencode($from_Currency);
    $to_Currency = urlencode($to_Currency);
    //www.google.com/ig/calculator?hl=en&q=1USD=?EUR
    $url = 'http://www.google.com/ig/calculator?hl=en&q=$amount$from_Currency=?$to_Currency';
    $ch = curl_init();
    $timeout = 0;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1)');
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    $rawdata = curl_exec($ch);
    curl_close($ch);
    $data = explode('"', $rawdata);
    $data = explode(',', $data['3']);
    $var = $data['0'];

    return round($var, 2);                  

}
echo currency("USD", "EUR", 1);
?>

anyone could suggest what is wrong here?

thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T04:07:43+00:00Added an answer on June 9, 2026 at 4:07 am

    Using single quotes will mean that variables do not expand. Use double quotes instead, or concat the string into multiple pieces.

    $url = "http://www.google.com/ig/calculator?hl=en&q=$amount$from_Currency=?$to_Currency";
    //or
    $url = 'http://www.google.com/ig/calculator?hl=en&q=' . $amount . $from_Currency . '=?' . $to_Currency;
    
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