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Home/ Questions/Q 4254142
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T05:02:32+00:00 2026-05-21T05:02:32+00:00

I am trying to use Jquery Validate and making a call to a webservice

  • 0

I am trying to use Jquery Validate and making a call to a webservice to validate a field. But when I do this I get the Firebug error :

invalid label
{“d”:false}

Here is my code, can anybody help?

$("form").validate({
         //errorLabelContainer: $("#divErrors"),

             rules: {
                 txtUserName: {
                     required: true,
                     minlength: 4,
                     maxlength: 20,
                     remote: function() {
                         var r = {
                             type: "POST",
                             url: "/Services/CDServices.asmx/CheckForUniqueUserName",
                             contentType: "application/json; charset=utf-8",
                             dataType: "json",
                             data: "{'strUserName':'" + $('input[name="txtUserName"]').val() + "'}"
                         }
                         return r;
                     }
                 }

[WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public bool CheckForUniqueUserName(string strUserName)
    {
        return false;
    }
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  1. Editorial Team
    Editorial Team
    2026-05-21T05:02:32+00:00Added an answer on May 21, 2026 at 5:02 am

    In your case you can use dataFilter function to “unwrap” your result, like this:

    $("form").validate(
      //errorLabelContainer: $("#divErrors"),
      rules: {
        txtUserName: {
          required: true,
          minlength: 4,
          maxlength: 20,
          remote: function() {
            var r = {
              type: "POST",
              url: "/Services/CDServices.asmx/CheckForUniqueUserName",
              contentType: "application/json; charset=utf-8",
              dataType: "json",
              data: "{'strUserName':'" + $('input[name="txtUserName"]').val() + "'}",
              dataFilter: function (data, dataType) {
                if (dataType == "json") {
                  var result = $.parseJSON(data);
                  if (result.d) {
                    return result.d;
                  } else {
                    return data;
                  }
                } else {
                  return data;
                }
              }
            }
            return r;
          }
        }
      }
    });
    
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