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Home/ Questions/Q 355895
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T12:03:38+00:00 2026-05-12T12:03:38+00:00

I am trying to use parameter substitution with SQLite within Python for an IN

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I am trying to use parameter substitution with SQLite within Python for an IN clause. Here is a complete running example that demonstrates:

import sqlite3

c = sqlite3.connect(":memory:")
c.execute('CREATE TABLE distro (id INTEGER PRIMARY KEY AUTOINCREMENT, name TEXT)')

for name in 'Ubuntu Fedora Puppy DSL SuSE'.split():
  c.execute('INSERT INTO distro (name) VALUES (?)', [ name ] )

desired_ids = ["1", "2", "5", "47"]
result_set = c.execute('SELECT * FROM distro WHERE id IN (%s)' % (", ".join(desired_ids)), ())
for result in result_set:
  print result

It prints out:

(1, u’Ubuntu’)
(2, u’Fedora’)
(5, u’SuSE’)

As the docs state that “[y]ou shouldn’t assemble your query using Python’s string operations because doing so is insecure; it makes your program vulnerable to an SQL injection attack,” I am hoping to use parameter substitution.

When I try:

result_set = c.execute('SELECT * FROM distro WHERE id IN (?)', [ (", ".join(desired_ids)) ])

I get an empty result set, and when I try:

result_set = c.execute('SELECT * FROM distro WHERE id IN (?)', [ desired_ids ] )

I get:

InterfaceError: Error binding parameter 0 – probably unsupported type.

While I hope that any answer to this simplified problem will work, I would like to point out that the actual query I want to perform is in a doubly-nested subquery. To wit:

UPDATE dir_x_user SET user_revision = user_attempted_revision 
WHERE user_id IN 
    (SELECT user_id FROM 
        (SELECT user_id, MAX(revision) FROM users WHERE obfuscated_name IN 
            ("Argl883", "Manf496", "Mook657") GROUP BY user_id
        ) 
    )
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T12:03:38+00:00Added an answer on May 12, 2026 at 12:03 pm

    You do need the right number of ?s, but that doesn’t pose a sql injection risk:

    >>> result_set = c.execute('SELECT * FROM distro WHERE id IN (%s)' %
                               ','.join('?'*len(desired_ids)), desired_ids)
    >>> print result_set.fetchall()
    [(1, u'Ubuntu'), (2, u'Fedora'), (5, u'SuSE')]
    
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