Question

I am trying to use php to get an image from an array in Drupal. At the moment when printing this array other variables are printed as well. What i need is a way to search this array for an image such as this ->

<img src="blah.jpg" alt="blah" />

and then save this as a separate variable. I’m unsure how to approach this sort of problem.

Perhaps a regex function or another in built php function?

I would class my knowledge as pretty low in php so please make your answer as simple as possible

Answer 1

Here, I found this (first result when you Google php regex img tag). This show you the required Regular Expression.

$content = 'This is a test. <img src="images/foo.jpg" title="foo">';
$res = preg_match_all('/<img[^>]*>/Ui', $content, $matches);
$string =  $matches[0][0];

I don’t really get your whole array question, but this should probably be enough to achieve your goal!

Good luck!