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Home/ Questions/Q 6851881
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T01:18:07+00:00 2026-05-27T01:18:07+00:00

I am trying to use Python in order to manipulate a text file from

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I am trying to use Python in order to manipulate a text file from Format A:

Key1  
Key1value1  
Key1value2  
Key1value3  
Key2  
Key2value1  
Key2value2  
Key2value3  
Key3... 

Into Format B:

Key1 Key1value1  
Key1 Key1value2  
Key1 Key1value3  
Key2 Key2value1  
Key2 Key2value2  
Key2 Key2value3  
Key3 Key3value1...

Specifically, here is a brief look at the file itself (only one key shown, thousands more in the full file):

chr22:16287243: PASS  
patientID1  G/G  
patientID2  G/G  
patient ID3 G/G

And the desired output here:

chr22:16287243: PASS  patientID1    G/G  
chr22:16287243: PASS  patientID2    G/G  
chr22:16287243: PASS  patientID3    G/G

I’ve written the following code which can detect/display the keys, but I am having trouble writing the code to store the values associated with each key, and subsequently printing these key-value pairs. Can anyone please assist me with this task?

import sys
import re

records=[]

with open('filepath', 'r') as infile:
    for line in infile:
        variant = re.search("\Achr\d",line, re.I) # all variants start with "chr"
        if variant:
            records.append(line.replace("\n",""))
            #parse lines until a new variant is encountered

for r in records:
    print (r)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T01:18:08+00:00Added an answer on May 27, 2026 at 1:18 am

    Do it in one pass, without storing the lines:

    with open("input") as infile, open("ouptut", "w") as outfile:
        for line in infile:
            if line.startswith("chr"):
                key = line.strip()
            else:
                print >> outfile, key, line.rstrip("\n")
    

    This code assumes the first line contains a key and will fail otherwise.

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