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Home/ Questions/Q 1115825
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T03:12:46+00:00 2026-05-17T03:12:46+00:00

I am trying to use Python (through Django framework) to make a Linux command

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I am trying to use Python (through Django framework) to make a Linux command line call and have tried both os.system and os.open but for both of these it seems that the Python script hangs after making the command line call as the call is for instantiating a server (so it never “finishes” as its meant to be long-running). I know for doing something like this with other Python code you can use something like celery but I figured there would be a simple way to get it to just make a command line call and not be “tied into it” so that it can just move past, I am wondering if I am doing something wrong… thanks for any advice.

I am making the call like this currently

os.system("command_to_start_server")

also tried:

response = os.popen("command_to_start_server")
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  1. Editorial Team
    Editorial Team
    2026-05-17T03:12:46+00:00Added an answer on May 17, 2026 at 3:12 am

    I’m not sure, but I think the subprocess module with its Popen is much more flexible than os.popen. If I recall correctly it includes asynchronous process spawning, which I think is what you’re looking for.

    Edit: It’s been a while since I used the subprocess module, but if I’m not mistaken, subprocess.Popen returns immediately, and only when you try to communicate with the process (such as reading its output) using subprocess.communicate does your program block waiting for output if there is none.

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