I am trying to use Pythons LXML library to create a GPX file that can be read by Garmin’s Mapsource Product. The header on their GPX files looks like this
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<gpx xmlns="http://www.topografix.com/GPX/1/1"
creator="MapSource 6.15.5" version="1.1"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd">
When I use the following code:
xmlns = "http://www.topografix.com/GPX/1/1"
xsi = "http://www.w3.org/2001/XMLSchema-instance"
schemaLocation = "http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd"
version = "1.1"
ns = "{xsi}"
getXML = etree.Element("{" + xmlns + "}gpx", version=version, attrib={"{xsi}schemaLocation": schemaLocation}, creator='My Product', nsmap={'xsi': xsi, None: xmlns})
print(etree.tostring(getXML, xml_declaration=True, standalone='Yes', encoding="UTF-8", pretty_print=True))
I get:
<?xml version=\'1.0\' encoding=\'UTF-8\' standalone=\'yes\'?>
<gpx xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.topografix.com/GPX/1/1" xmlns:ns0="xsi"
ns0:schemaLocation="http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd"
version="1.1" creator="My Product"/>
Which has the annoying ns0 tag. This might be perfectly valid XML but Mapsource does not appreciate it.
Any idea how to get this to not have the ns0 tag?
The problem is with your attribute name.
puts schemaLocation in the xsi namespace.
I think you meant
to use the URL for xsi. This matches your uses of namespace variables in the element name. It puts the attribute in the
http://www.w3.org/2001/XMLSchema-instancenamespaceThat gives the result of