Question

I am trying to use the code below to do the following;

1. In a MySQL table called submission,
   check to see if subcheck = 1 for the
   row where submissionid =
$submissionid.

2. If the answer to #1 above is yes, then take the email field from a MySQL table called “login” from the row where username = $submittor’, and then email $comment to that address.

It’s not working. Any ideas why not?

Thanks in advance,

John

$querye = mysql_query("SELECT subcheck FROM submission WHERE subcheck = '1' AND WHERE submissionid = '$submissionid' ");

if (mysql_num_rows($querye) == 1)
{

$mailaddress = "SELECT email FROM login WHERE username = '$submittor'";

$queryem = mail($mailaddress, "Someone has commented on your submission $submission.", $comment, "[e-mail]");

mysql_query($queryem) or die(mysql_error());

}
else
{
//your subcheck is not 1 / nothing was found
}

Answer 1

You are using $mailaddres before fetching it from DB.

You should do something like:

$email_query = "SELECT email FROM login WHERE username = '$submittor'";
$result = mysql_query($email_query);
if (!$result) {
        trigger_error('Invalid query: ' . mysql_error()." in ".$email_query);
}

if($row = mysql_fetch_assoc($result)) {
        $mailaddress = $row['email'];
        $queryem = mail($mailaddress, "Someone has commented on your submission 
                        $submission.", $comment, "[e-mail]");
}else{
        // no rows found.
}