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Home/ Questions/Q 8537909
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T11:00:55+00:00 2026-06-11T11:00:55+00:00

I am trying to use the following C code to print out an array

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I am trying to use the following C code to print out an array that I have passed in. It should output the text in hexadecimal format one on each line and I have no problems opening the file. When I first wrote it, I had no problems with it working I opened the output file and my array was there. I changed the fileOutName parameter and now I can’t get it to print out anything I have tried changing it back and to a few other things and nothing seems to work. Also when I debug it seems like pOutfile is a bad pointer, but like I said it still creates the file it just won’t write anything in it. Any help would be appreciated. Thanks

printoutput(int output[], char * fileOutName){
    int i = 0;
    FILE * pOutfile;
    pOutfile = fopen( fileOutName, "w" );
    while(output[i] != 0){
        fprintf( pOutfile, "0x%0.4X\n", output[i] );
        i++;
    }
}
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  1. Editorial Team
    Editorial Team
    2026-06-11T11:00:56+00:00Added an answer on June 11, 2026 at 11:00 am

    Always clean up after yourself. You’re missing an fclose(pOutfile).

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