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Home/ Questions/Q 7568515
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T14:56:45+00:00 2026-05-30T14:56:45+00:00

I am trying to use the PHP exec() function. If the return_var argument is

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I am trying to use the PHP exec() function.

If the return_var argument is present along with the output argument,
then the return status of the executed command will be written to this
variable.

If the execution was successful, it’s 0. However, if there is an error, it can be a multitude of other integers. I can’t seem to find anywhere what those integers correspond to. How should I interpret the integer that I get?

Update:

I really should have specified this originally, but I am executing another PHP script. Unlike rsync, which has exit values on its man page, I can’t find an equivalent for PHP.

So what I am doing is something like:

$rv = exec('php file.php', $out, $rv);
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  1. Editorial Team
    Editorial Team
    2026-05-30T14:56:46+00:00Added an answer on May 30, 2026 at 2:56 pm

    The return value is dependent on the process/program that you ran with exec. For instance, if you ran grep:

    The exit status is 0 if selected lines are found, and 1 if not
    found. If an error occurred the exit status is 2. (Note: POSIX
    error handling code should check for ‘2’ or greater.)

    rsync has about 20 different error exit codes, all painstakingly explained in the man page:

    http://linux.die.net/man/1/rsync

    so yes, it’s program-dependant 🙂

    Even if you’re running PHP script, the exit value depends on your program itself. By default php scripts will exit with 0. If you use the exit function you can return different exit codes:

    http://php.net/manual/en/function.exit.php

    If you want to experimentally determine what your php program exits, call it on the command line:

    php file.php
    

    then do

    echo $?
    

    this will show you the exit value of your php script.

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