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Home/ Questions/Q 7799079
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Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T00:11:35+00:00 2026-06-02T00:11:35+00:00

I am trying to work on the chainability in a jquery plugin, and it

  • 0

I am trying to work on the chainability in a jquery plugin, and it works fine with jquery click below,

$(document).ready(function(){


        $('.call-parent').parent_child({
            target: '.element'
        });

        $('.call-child-1').click(function(){
            $(this).parent_child().child_1();
            return false;
        });

        $('.call-child-2').click(function(){
            $(this).parent_child().child_2();
            return false;
        });

    });

(function($) {

        $.fn.extend({ 

            parent_child: function(options) {

                var defaults = {
                    target:''
                }

                var options = $.extend(defaults, options);
                var o = options;

                var $this = this;

                var $cm = this.click(function(ei) {


                    alert('parent');
                    $this.child_1();

                    return false;

                });


                $this.child_1 = function() {

                    alert('child 1');

                };


                $this.child_2 = function() {

                    alert('child 2');

                };

                return $cm;

            }
        })
    })(jQuery);​

but I have the error when I use each or ready in the plugin, for instance,

$(document).ready(function(){


        $('.call-parent').parent_child({
            target: '.element'
        });

        $('.call-child-1').click(function(){
            $(this).parent_child().child_1();
            return false;
        });

        $('.call-child-2').click(function(){
            $(this).parent_child().child_2();
            return false;
        });

    });

(function($) {

        $.fn.extend({ 

            parent_child: function(options) {

                var defaults = {
                    target:''
                }

                var options = $.extend(defaults, options);
                var o = options;

                var $this = this;

                var $cm = this.each(function(ei) {


                    alert('parent');
                    $this.child_1();

                    return false;

                });


                $this.child_1 = function() {

                    alert('child 1');

                };


                $this.child_2 = function() {

                    alert('child 2');

                };

                return $cm;

            }
        })
    })(jQuery);​

error message,

$this.child_1 is not a function [Break On This Error]

Why can’t I do that with each or ready? Or have I done it wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T00:11:37+00:00Added an answer on June 2, 2026 at 12:11 am

    I’m restating my comment as an answer so you can accept:

    Function expressions like var f = function() { ... } do not get hoisted the way named function declarations function f() { ... } do. So in the each example, setting $cm is calling $this.child_1 before it has been declared. In your first example, the function is called on click, so it has already been parsed by the time it is executed.

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