Question

I am trying to write a code that takes a URL that has 3 parts (www).(domainname).(com) and trim the first part out completely.

So far I have this code that checks if on the left side I don’t have a ‘www’ or ‘dev’
go in and set siteDomainName = removecharsCGI.SERVER_NAME,1,2);

if (numHostParts eq 3 and listfindnocase('www,dev',left(CGI.SERVER_NAME,3)) eq 0) {
        siteDomainName = removecharsCGI.SERVER_NAME,1,2);

The problem with the code above is that is deleting only 2 characters where I need it to delete ALL characters until numHostParts eq 2 or at least until the first “.”

Another example would be:

akjnakdn.example.com I need the code to delete the first part of the URL with the dot included (akjnakdn.)

This code will help some of the queries that i have on the site to stop crushing because they are related with the #URL# and when the #URL# is fake I am getting cform query returned zero records error that is causing my contact forms to stop working.

Answer 1

You could do something like this:

<cfscript> 
    local.nameArr = ListToArray(CGI.SERVER_NAME, '.');
    if (ArrayLen(local.nameArr) gt 2) {
        ArrayDeleteAt(local.nameArr, 1);
    }
    siteDomainName = ArrayToList(local.nameArr, '.');
</cfscript>

I’ve split the server name into array elements with a period as the delimiter. If the number of elements is greater than two, remove the first element. Then convert it back to a list with the period as a delimiter.

UPDATE

As suggested by Robb, this could be more concise and perform better by skipping the array conversion process:

<cfscript> 
    siteDomainName = CGI.SERVER_NAME;
    if (ListLen(siteDomainName, '.') gt 2) {
        siteDomainName = ListDeleteAt(siteDomainName, 1, '.');
    }
</cfscript>