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Home/ Questions/Q 6954461
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:36:34+00:00 2026-05-27T14:36:34+00:00

I am trying to write a code to remove all the leading, trailing and

  • 0

I am trying to write a code to remove all the leading, trailing and middle of the sentence spaces but to keep only one space between the words.

For example if the input is

"    This    is my     string    "

the output should be

"This is my string"

So far I have come up with this:

#include <stdio.h>
void cascade(char str[], int i);
main()
{
    char str[100] = "    This    is my     string    ";
    int i = 0;
    while (str[i] != '\0') {
            if (str[i] == ' ' && str[i + 1] == ' ')
                    cascade(str, i);
            i++;
    }
    printf("%s\n", str);
}

void cascade(char str[], int i)
{
    while(str[i] != '\0') {
            str[i] = str[i + 1];
            i++;
    }
    str[i + 1] = '\0';
}

I would appreciate if anyone could come up with some ideas, Thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:36:34+00:00Added an answer on May 27, 2026 at 2:36 pm
    #include <stdio.h>
    #include <string.h>
    
    char* trim(char str[]){
        char *p=str;
        char *token;
        if(str == NULL) return NULL;
        if(*str == '\0') return str;
    
        token=strtok(str, " \t");
        if(token == NULL){
            *str = '\0';
            return str;
        }
        while(NULL!=token){
            int len;
            len = strlen(token);
            if(p != token){
                memmove(p, token, len);
            }
            p += len;
            *p++ =' ';
            token = strtok(NULL, " \t");
        }
        p[-1]='\0';
    
        return str;
    }
    
    int main(){
        char str[100] = "    This    is my     string    ";
        printf("\"%s\"\n", trim(str));
        return 0;
    }
    
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