Question

I am trying to write a number guessing program as follows:

def oracle():
    n = ' '
    print 'Start number = 50'
    guess = 50 #Sets 50 as a starting number
    n = raw_input("\n\nTrue, False or Correct?: ")
    while True:
        if n == 'True':
            guess = guess + int(guess/5)
            print
            print 'What about',guess, '?'
            break
        elif n == 'False':
            guess = guess - int(guess/5)
            print
            print 'What about',guess, '?'
            break
        elif n == 'Correct':
            print 'Success!, your number is approximately equal to:', guess

oracle()

What I am trying to do now is get this sequence of if/ elif/ else commands to loop until the user enters ‘Correct’, i.e. when the number stated by the program is approximately equal to the users number, however if I do not know the users number I cannot think how I could implement and if statement, and my attempts to use ‘while’ also do not work.

Answer 1

As an alternative to @Mark Byers’ approach, you can use while True:

guess = 50     # this should be outside the loop, I think
while True:    # infinite loop
    n = raw_input("\n\nTrue, False or Correct?: ")
    if n == "Correct":
        break  # stops the loop
    elif n == "True":
        # etc.