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Home/ Questions/Q 6116989
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:16:10+00:00 2026-05-23T15:16:10+00:00

I am trying to write a part of a multithreaded program where each thread

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I am trying to write a part of a multithreaded program where each thread from a fixed thread pool tries to fetch an object from a Queue and if the Queue is empty the thread waits.

The problem I am experiencing is that the memory used by the program keeps increasing.

public class Ex3 {

public static LinkedBlockingQueue<Integer> myLBQ = new LinkedBlockingQueue<Integer>(10);

public static void main(String argc[]) throws Exception {
    ExecutorService executor = Executors.newFixedThreadPool(3);
    myLBQ.add(new Integer(1));
    for (;;) {
        executor.execute(new MyHandler(myLBQ));
    }
}
}

class MyHandler implements Runnable {

LinkedBlockingQueue<Integer> myLBQ;

MyHandler(LinkedBlockingQueue<Integer> myLBQ) {
    this.myLBQ = myLBQ;
}

public void run() {
    try {
        myLBQ.take();
    } catch (InterruptedException e) {
        e.printStackTrace();
    }
}
}

I don’t understand why the executor.execute keeps firing when the threads should be waiting for an item to be added to the Queue. How do I modify my code to reflect this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:16:10+00:00Added an answer on May 23, 2026 at 3:16 pm

    This adds tasks to the executor as fast as it can.

    for (;;) {
        executor.execute(new MyHandler(myLBQ));
    }
    

    This will consume about 200 MB per second. It doesn’t have anything to do with whether there are tasks to perform or not.

    If you don’t want to do this I suggest you move the loop to the runnable and add only one. This will cause it to wait for tasks forever.


    A better approach is to use the ExecutorService’s builtin queue to queue tasks.

    ExecutorService executor = Executors.newFixedThreadPool(3);
    final int taskId = 1;
    executor.submit(new Runnable() {
        @Override
        public void run() {
            doSomething(taskId);
        }
    });
    
    executor.shutdown();
    

    This does the same thing, but is much simpler IMHO.

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