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Home/ Questions/Q 6693653
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:00:31+00:00 2026-05-26T06:00:31+00:00

I am trying to write a Recursive Bubble sort in Java and I’m getting

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I am trying to write a Recursive Bubble sort in Java and I’m getting an Index Out of Bounds Exception. What am I doing wrong and why am I getting this error?
Here is my code:

public static  <T extends Comparable< ? super T>>
    void sort(T [] a){
    T tmp;
    for(int i=0;i<a.length;i++){
        if(a[i].compareTo(a[i+1])>0){
            tmp = a[i];
            a[i]=a[i+1];
            a[i+1]=tmp;
            sort(a);
        }
        System.out.println("i:"+i+" "+a[i]);

    }

Also, even tho it sorts the array and I get the error at the end, it is printing all of the steps, how do I make it print the last final sorted array?
Is probably a simple answer but my brain is fried right now and can’t think straight.
Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-26T06:00:31+00:00Added an answer on May 26, 2026 at 6:00 am

    The loop should stop when i < a.length-1 , because in your code you access the position i+1, and when i == a.length - 1 then i+1 will be trying to access an element off the end of the array that doesn’t exist – hence, out of bounds.

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