Question

I am trying to write a regex that matches all numbers (0-9) and # @ % signs.

I have tried ^[0-9#%@]$ , it doesn’t work.

I want it to match, for example: 1234345, 2323, 1, 3@, %@, 9, 23743, @@@@@, or whatever…

There must be something missing?

Thank you

Answer 1

You’re almost right… All you’re missing is something to tell the regular expression there may be more than once of those characters like a * (0 or more) or a + (1 or more).

^[0-9#%@]+$

The ^ and $ are used do indicate the start and end of a string, respectively. Make sure that you string only contains those characters otherwise, it won’t work (e.g. “The number is 89#1” wouldn’t work because the string begins with something other than 0-9, #, %, or @).