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Home/ Questions/Q 731933
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:05:03+00:00 2026-05-14T07:05:03+00:00

I am trying to write a simple activity that received from the user its

  • 0

I am trying to write a simple activity that received from the user its name and printing “hello + username” message.

the problem is that i cannot access to the username input via code.

the function is:

static ActivityBuilder CreateTask1()
    {
        Dictionary<string, object> properties = new Dictionary<string, object>();
        properties.Add("User_Name", new InArgument<string>());

        var res = new ActivityBuilder();

        res.Name = "Task1";

        foreach (var item in properties)
        {
            res.Properties.Add(new DynamicActivityProperty { Name = item.Key, Type = item.Value.GetType(), Value = item.Value });
        }

        Sequence c = new Sequence();

        c.Activities.Add(new WriteLine { Text = "Hello " + properties["User_Name"] });

        res.Implementation = c;

        return res;
    }

The output of the followed will always be “Hello User_Name”.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:05:04+00:00Added an answer on May 14, 2026 at 7:05 am

    OK I have found the answer (and the new magical “VisualBasicValue” class):

    static ActivityBuilder CreateTask1()
        {
            Dictionary<string, object> properties = new Dictionary<string, object>();
            properties.Add("User_Name", new InArgument<string>());
    
            var res = new ActivityBuilder();
    
            res.Name = "Task1";
    
            foreach (var item in properties)
            {
                res.Properties.Add(new DynamicActivityProperty { Name = item.Key, Type = item.Value.GetType(), Value = item.Value });
            }
    
            Sequence c = new Sequence();
    
            c.Activities.Add(new WriteLine { Text = new VisualBasicValue<string> { ExpressionText = "\"Hello \" + User_Name" } });
    
            res.Implementation = c;
    
            return res;
        }
    
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