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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T14:48:20+00:00 2026-05-12T14:48:20+00:00

I am trying to write a simple C calculator script, using only the basic

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I am trying to write a simple C calculator script, using only the basic +, -, /, *. I have the following, but I’m not sure why it’s not printing correctly.

#include<stdio.h>
#include<stdlib.h>

int main (void)
{

    //introduce vars
    double number1, number2, result;
    char symbol; //the operator *, -, +, /

    //allow user interaction
    printf("Enter your formula \n");
    scanf("%f %c %f", &number1, &symbol, &number2);

    switch (symbol) {
        case '+':
            result = number1 + number2;
            break;
        default:
            printf("something else happened i am not aware of");
            break;
    }

    getchar();
    return 0;
}

Why is the result not being printed? Am I doing something wrong here,

result = number1 + number2;
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  1. Editorial Team
    Editorial Team
    2026-05-12T14:48:21+00:00Added an answer on May 12, 2026 at 2:48 pm

    “Why is the result not being printed?”

    You calculate the answer properly, but do not print it anywhere.

    You need to have something like:

    printf("Answer: %f + %f = %f\n", number1, number2, result);
    

    Without a print statement, nothing gets printed.


    EDIT Responding to comment:

    Did you do the printf after you calculate the result?
    Personally, I would put the printf just before the getchar();

    For more debugging, just after your scanf, I would write:

    printf("Input as received: number1 is %f\n number2 is %f\nsymbol is %c\n", number1, number2, symbol);
    

    If that does not show the input that you typed, then something is wrong with how you gather input.

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