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Home/ Questions/Q 6182859
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:16:12+00:00 2026-05-24T01:16:12+00:00

I am trying to write a simple jQuery plugin just to see how its

  • 0

I am trying to write a simple jQuery plugin just to see how its done. But i cant seem to run it twice simultaneously. Its basically a count down and all it does is get the text() value in a div and count it down until it reaches 1.

$('#box1').startCounter();
$('#box2').startCounter();

This call changes both this variables inside the function to point to #box2. Here is my jsfiddle

Its pretty confusing how this changes around in a jQuery plugin. thanks for any help 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:16:13+00:00Added an answer on May 24, 2026 at 1:16 am

    You defined $this in global scope, so when startCount is called on the second element, the value is overwritten. Use var to make it local:

    var $this = this;
    

    DEMO


    Instead of invoking the function again the element, you could also do something like this:

    $.fn.startCount = function(count, div) {
        count = (count) ? count : parseInt($('span.no-display',this).text());
        var $target =  $('div.counter', this);
    
        var run = function() {
            if (count <= 1) {
                this.fadeOut().mouseout();
            }       
            else {
                count--;
                $target.text(count);
                setTimeout(run, 1000);
            }
        };
        run();
    }
    

    DEMO 2


    And to make your plugin work in environments where $ does not refer to jQuery (jQuery.noConflict()), you should do:

    (function($) {
        $.fn.startCount = ...
    }(jQuery)); 
    
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