Question

i am trying to write an xslt code that will check whether the description element exist or not if it exist then it will show the description element but if it does not exist then it should not show the description element.but my code below still show element although there is no value in it.how can we code it so that it wont show out the description element if there is no description for a services.

  <?xml version="1.0" encoding="UTF-8"?>
  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">


   <xsl:template match="Service">
     <xsl:element name="equipment">
      <xsl:if test="description !='' ">
          <xsl:value-of select="description" />
      </xsl:if>
      <xsl:if test="not(description)">
      </xsl:if>
     </xsl:element>
    </xsl:template>
   </xsl:stylesheet>

as there is the an empty equipment element being returned.i want it to return only the first 2 equipment element that is not empty.

Answer 1

     <xsl:template match="/">
  <xsl:apply-templates select="//Service"/>
  </xsl:template>
<xsl:template match="Service">
      <xsl:if test="description !='' ">
           <xsl:element name="equipment">
          <xsl:value-of select="description" />
     </xsl:element>
      </xsl:if>
    </xsl:template>

or

 <xsl:template match="/">
  <xsl:apply-templates select="//Service"/>
  </xsl:template>
   <xsl:template match="Service">
      <xsl:if test="child::description[text()]">
       <xsl:element name="equipment">
          <xsl:value-of select="description" />
            </xsl:element>
      </xsl:if>
    </xsl:template>