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Home/ Questions/Q 7874337
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T02:47:14+00:00 2026-06-03T02:47:14+00:00

I am unsure why, but it seems that when I call $.getJSON after another

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I am unsure why, but it seems that when I call $.getJSON after another getJson has been called, nothing happens. Here is the code:

getWeather();

function getWeather() {
    $.getJSON("http://where.yahooapis.com/geocode?q=" + lat + ",+" + lon + "&gflags=R&flags=J", function(data){
        zipCode = data.ResultSet.Results[0].postal;
        WOEID = data.ResultSet.Results[0].woeid;
        getYahooWeather(WOEID);         
    });
}

function getYahooWeather(x) {
    var query = escape('select item from weather.forecast where woeid="'+x+'"');
    var url = "http://query.yahooapis.com/v1/public/yql?q=" + query + "&format=json&callback=c";
    console.log(url);

    $.getJSON(url, function(data2){
        console.log("hey");
    });
}

My question is, am I doing something wrong with these $.getJSON calls?

Thanks so much

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  1. Editorial Team
    Editorial Team
    2026-06-03T02:47:15+00:00Added an answer on June 3, 2026 at 2:47 am

    You have specified that the callback should be the c function, so declare it:

    function getYahooWeather(x) {
      var query = escape('select item from weather.forecast where woeid="'+x+'"');
      var url = "http://query.yahooapis.com/v1/public/yql?q=" + query + "&format=json&callback=c";
      console.log(url);
    
      $.getJSON(url);
    }
    
    function c(data2) {
      console.log("hey");
    }
    
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