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Home/ Questions/Q 8132911
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T09:27:36+00:00 2026-06-06T09:27:36+00:00

I am used to Java and new to QT/C++, and I have some problems

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I am used to Java and new to QT/C++, and I have some problems creating a QLabel which changes text whenever a person is selecting a QListWidgetItem.

In my ui_GraphicsView.h I have setupUI() which makes the objects.
I try to make a layout its parent.

label = new QLabel(verticalLayout);
   label->setObjectName(QString::fromUtf8("label"));
   verticalLayout->addWidget(label);

In my .cpp-file I make use of connect in the constructor:

connect(list_widget, SIGNAL(itemSelectionChanged(), this, SLOT(updataDetails())));

updateDetails() is executed in my selectionChanged() method where it passes a string.

void GraphicsView::updateDetails(QString details){
    label->setText(details);
}

This is resulting in the following error:

error: no matching function for call to ‘QLabel::QLabel(QVBoxLayout*&)
note: candidates are: QLabel::QLabel(const QLabel&)
note: QLabel::QLabel(const QString&, QWidget*, Qt::WindowFlags)
note: QLabel::QLabel(QWidget*, Qt::WindowFlags)

Everything worked out well before I made the adjustments described above. Any idea what is causing this error?

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  1. Editorial Team
    Editorial Team
    2026-06-06T09:27:39+00:00Added an answer on June 6, 2026 at 9:27 am

    Read the error. QLabel::QLabel is constructor. Constructor expects pointer to widget, not to layout.
    In fact, you want to do following:

    label = new QLabel(parent_widget);
    label->setLayout(layout)
    

    EDIT: Strange, nobody noticed my error. Setting layout on label is strange. Better is

    label=new QLabel();
    layout->addWidget(label).
    

    Label will get owner of layout as parent.

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